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Circular polarised wave

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In this I could not understand why D option is wrong .
As both dy/dt and dz/dt are dependent on x and time

asked May 9, 2017 in Physics Problems by koolman (4,286 points)

1 Answer

1 vote
 
Best answer

The particle speed $v=\sqrt{\dot y^2+\dot z^2}$.

$\dot y=-\omega a \cos\phi$
$\dot z=+\omega a\sin\phi$
where $\phi=kx-\omega t$.

So although $\dot y, \dot z$ each depend on $x, t$ the combination $v=\sqrt{\dot y^2+\dot z^2}=\omega a=$ constant does not depend on either $x$ or $t$.

answered May 9, 2017 by sammy gerbil (28,876 points)
edited May 10, 2017 by sammy gerbil
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