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magnetic field outside the conductor

1 vote

I think B option should be correct .
As by using amphere circuital law , consider a loop of radius r .
$B(2\pi r)=\mu i$
i we have calculated in option A.

asked May 14, 2017 in Physics Problems by koolman (4,286 points)
Please show your calculation.

1 Answer

1 vote

Outside of the conductor, the magnetic field at radius $r$ is given by Ampere's Circuit Law :
$B(2\pi r)=\mu_0 I=\mu_0 (\frac13 J_0 \pi a^2)$
in which I have used the result from (A). Therefore
$B=\mu_0 J_0 \frac{a^2}{6r}$
so answer (B) is not correct.

answered May 18, 2017 by sammy gerbil (28,178 points)