>The plates of a parallel plate capacitor are separated by a distance d = 1 cm. Two parallel sided dielectric slabs of thickness 0.7 cm and 0.3 cm fill the space between the plates. If the dielectric constants of the two slabs are 3 and 5 respectively and a potential difference of 440V is applied across the plates. Find : the electric field intensities in each of the slabs.

My try

Now how to proceed ?

Assuming that your 2 equations are correct, from the 1st you can find $Q/\epsilon_0 A$ and then substitute into the 2nd equation.

edited Jan 2, 2017 by sammy gerbil