This is very similar to your other recent question potential difference across inductor. The only significant difference is that you now have capacitors in the circuit as well as inductors.
Capacitors store voltage whereas inductors store current. Follow the same method of solution as in the linked question. That is : (1) find the steady-state currents through the inductors and voltages on the capacitors; (2) when the battery has been disconnected replace each capacitor and inductor by an ideal battery (no internal resistance). The capacitor batteries will have the steady state voltage - in sign as well as magnitude. The inductor batteries have unknown voltages, which can be found by applying Kirchhoff's Laws, and are such that the steady state currents continue to flow through each.
Note that charge can flow "through" capacitors in the transient state (immediately after the battery is disconnected) but not in the steady state. Also, the voltmeter has infinite resistance so effectively no charge flows through it - both in the steady state and the transient state..