Physics Problems Q&A - Recent questions in Physics Problems
http://physics.qandaexchange.com/?qa=questions/physics-problems
Powered by Question2Answertime required to pass electricity through electroplating bath
http://physics.qandaexchange.com/?qa=3447/time-required-pass-electricity-through-electroplating-bath
<p>The time required to pass 3600 Coulomb of electricity through an electroplating bath using a current of 200 mA is <strong><strong>__</strong></strong>_ hours</p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3447/time-required-pass-electricity-through-electroplating-bathWed, 17 Apr 2019 03:09:40 +0000Container filled with fluid move with a acceleration a
http://physics.qandaexchange.com/?qa=3446/container-filled-with-fluid-move-with-a-acceleration-a
<p><img src="https://i.imgur.com/2lDHr3Z.jpg" alt=""></p>
<p>My try : </p>
<p><img src="https://i.imgur.com/5rhhb1t.jpg" alt=""></p>
<p>My option B is not getting matched.<br>
Answer is given as B, C.</p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3446/container-filled-with-fluid-move-with-a-acceleration-aTue, 16 Apr 2019 15:23:24 +0000Calculating equivalent capacitance.
http://physics.qandaexchange.com/?qa=3442/calculating-equivalent-capacitance
<blockquote><p>A parallel plate capacitor of capacitance $C$ without dielectrics is filled by a dielectric slab as shown <a rel="nofollow" href="https://pasteboard.co/I9lgDqO.png">here</a>, the new capacitance will be?</p>
</blockquote>
<p><img src="https://i.imgur.com/lhSXbwo.png" alt=""></p>
<p>When I solve it in two ways as shown <a rel="nofollow" href="https://pasteboard.co/I9lhJYk.png">here</a> I got different results as $3.9C$ and $4C$ respectively, why? And which one is correct, please help.<br>
<img src="https://i.imgur.com/4gEkS5x.png" alt=""></p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3442/calculating-equivalent-capacitanceTue, 09 Apr 2019 13:46:03 +0000Velocity of image of submerged object when liquid surface moves
http://physics.qandaexchange.com/?qa=3437/velocity-image-submerged-object-when-liquid-surface-moves
<blockquote><p>Speed of the image (as seen by an observer in air) of the coin if the liquid surface is raised with speed $8\ m/s$<br>
<img src="https://i.imgur.com/jLiy7jG.png" alt=""><br>
I know how to deal with when the object is moving but how to do when surface moves?</p>
</blockquote>
Physics Problemshttp://physics.qandaexchange.com/?qa=3437/velocity-image-submerged-object-when-liquid-surface-movesMon, 08 Apr 2019 10:48:47 +0000Minimum force required to rotate a lamina when there is friction
http://physics.qandaexchange.com/?qa=3433/minimum-force-required-to-rotate-lamina-when-there-friction
<blockquote><p>A uniform right-angled lamina is placed on a horizontal floor which is not frictionless. One of the acute angles of the lamina is $\theta$. If $F_a$ and $F_b$ are the minimum forces required to rotate the lamina about stationary vertical axes through the vertices A and B respectively, find the minimum force required to rotate the lamina about a stationary vertical axis through the vertex C.</p>
</blockquote>
Physics Problemshttp://physics.qandaexchange.com/?qa=3433/minimum-force-required-to-rotate-lamina-when-there-frictionSat, 06 Apr 2019 06:54:35 +0000Increasing resistance with temperature.
http://physics.qandaexchange.com/?qa=3432/increasing-resistance-with-temperature
<blockquote><p>When a bulb, connected across potential $V$ of initial resistance $R_o$ is switched on its resistance increases due to heat production. Assuming initial temperatures of the bulb is $0^{\circ}C$, and temperature coefficient of the bulb is $\alpha$. After what time its temperature will become $T$. The heat capacity of the bulb is $c$.</p>
</blockquote>
<p>I only know that $R=R_o\cdot e^{\alpha\cdot (T_2-T_1)}$ how do I apply it here, please help?</p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3432/increasing-resistance-with-temperatureWed, 03 Apr 2019 14:42:27 +0000Given the vector current density, determine the total current flowing outward through a circular band
http://physics.qandaexchange.com/?qa=3431/current-density-determine-current-flowing-outward-circular
<p>Given the vector current density, determine the total current flowing outward through a circular band.:</p>
<p><a rel="nofollow" href="https://i.stack.imgur.com/klQAo.png"><img src="https://i.stack.imgur.com/klQAo.png" alt="enter image description here"></a></p>
<p>The answer should be 518A. It comes something around 3255 A. Where is the mistake?</p>
<p><a rel="nofollow" href="https://i.stack.imgur.com/g1T1l.jpg"><img src="https://i.stack.imgur.com/g1T1l.jpg" alt="enter image description here"></a></p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3431/current-density-determine-current-flowing-outward-circularFri, 29 Mar 2019 11:20:51 +0000Nucleon-Nucleon Scattering
http://physics.qandaexchange.com/?qa=3430/nucleon-nucleon-scattering
<p><img src="https://i.imgur.com/hZhT97F.png[/img]" alt=""><br>
<img src="https://i.imgur.com/rklrj0w.jpg[/img]" alt=""></p>
<p>I computed the orbital angular momentum classically, and then used quantum mechanics. But I am not convinced of what I got, because $L \alpha \sqrt{E}$ is a proportional equation that does not justify that when E < 20 MeV you get L ~ 0 (I do not see, numerically speaking, the difference between either plugging 20 MeV or 19MeV).</p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3430/nucleon-nucleon-scatteringWed, 27 Mar 2019 12:38:33 +0000Where do I make the approximations in this proton and electron collision problem?
http://physics.qandaexchange.com/?qa=3407/where-make-approximations-proton-electron-collision-problem
<blockquote><p>A proton moving with a velocity $\beta c$ collides with a stationary electron of mass $m$ and knocks it off at an angle $\theta$ with the incident direction. Show that the energy imparted to the electron is approximately $$T \approx \frac{2\beta^2 \cos^2\theta}{1-\beta^2\cos^2\theta}mc^2$$</p>
</blockquote>
<p><em>Link to question :</em><br>
<a rel="nofollow" href="https://www.chegg.com/homework-help/questions-and-answers/proton-moving-velocity-collides-stationary-electron-mass-m-knocks-angle-incident-direction-q35643739?trackid=VRP2b2Jt">https://www.chegg.com/homework-help/questions-and-answers/proton-moving-velocity-collides-stationary-electron-mass-m-knocks-angle-incident-direction-q35643739?trackid=VRP2b2Jt</a></p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3407/where-make-approximations-proton-electron-collision-problemSun, 17 Mar 2019 04:34:00 +0000How to apply the gauss law when charge density is a function of not only $r$?
http://physics.qandaexchange.com/?qa=3416/how-apply-the-gauss-law-when-charge-density-function-not-only
<p>The problem goes as </p>
<blockquote><p>A sphere of radius R, centre at origin carries charges with density $\rho(r,\theta)= \frac{KR(R-2r)sin\theta}{r^2}$ where K is a constant and $r,\theta$ are usual spherical co-ordinates. Find the potential and field for points on the $z$ axis far from the centre. </p>
</blockquote>
<p>Now in that question how can I apply Gauss' Law because the equipotential surfaces would not be sphere anymore? </p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3416/how-apply-the-gauss-law-when-charge-density-function-not-onlySun, 17 Mar 2019 04:33:56 +0000Problem 5.13 Griffiths; Balancing magnetic attraction with electrical repulsion
http://physics.qandaexchange.com/?qa=3412/griffiths-balancing-magnetic-attraction-electrical-repulsion
<p><img src="https://i.imgur.com/FXLVcBI.png[/img]" alt=""></p>
<p><img src="https://i.imgur.com/PMivCmW.png[/img]" alt=""></p>
<p><img src="https://i.imgur.com/YY66H4H.png[/img]" alt=""></p>
<p>I do not get why it is argued that the balancing is impossible; in fact, we are working with line charges, which do travel at the speed of light. </p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3412/griffiths-balancing-magnetic-attraction-electrical-repulsionThu, 14 Mar 2019 17:49:57 +0000Maximum charge and maximum current
http://physics.qandaexchange.com/?qa=3406/maximum-charge-and-maximum-current
<p><img src="https://i.imgur.com/KvunUGd.jpg" alt=""><br>
<img src="https://i.imgur.com/Am0TnRX.jpg" alt=""></p>
<p>My try :</p>
<p><img src="https://i.imgur.com/y81hQwo.jpg" alt=""></p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3406/maximum-charge-and-maximum-currentMon, 11 Mar 2019 01:57:30 +0000Griffiths 5.4 Force on a square loop
http://physics.qandaexchange.com/?qa=3404/griffiths-5-4-force-on-a-square-loop
<p><img src="https://i.imgur.com/HckbPJf.png[/img]" alt=""></p>
<p><img src="https://i.imgur.com/9SEg3Li.png[/img]" alt=""></p>
<p>Before doing any calculation, I see the net force being zero;</p>
<p>$$ F_{AB} = -F_{CD}$$</p>
<p>$$ F_{BC} = -F_{DA}$$ </p>
<p>But apparently this is not the case. The provided solution is:</p>
<p><img src="https://i.imgur.com/75ijztI.png[/img]" alt=""></p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3404/griffiths-5-4-force-on-a-square-loopSat, 09 Mar 2019 11:53:06 +0000How to induce large current in flexible wire and explaining how does it stretch into a circle
http://physics.qandaexchange.com/?qa=3401/induce-large-current-flexible-explaining-does-stretch-circle
<blockquote><p>The idea is to explain how could we induce current in a flexible loop using an initially free-of-current wire.</p>
</blockquote>
<p><strong>Some background.</strong></p>
<p>The current has to be the same all the way around (otherwise charge would be gathered at some point and in that accumulation of charge, the electric field would point in a way that the flow would even out). </p>
<p>The two forces involved in driving the current around the loop are the source force (typically a battery) and the electrostatic force, which smooths out the flow. The line integral of the vector sum of the previous forces is known as electromotive force (emf).</p>
<p><strong>My answer to the problem</strong> </p>
<p>My difficulty in this problem is that I do not have clear the sketch. I would say that the following happens:</p>
<p>Imagine that the loop is in the xy plane. The velocity of the current is tangential to the loop and its direction is clockwise; $B$ will point in the $-z$ direction and the force will point radially outwards. This force would be the source one (provided by the battery and the one that does work to move the loop; I know magnetic force does no work; the individual radial vectors of the force do work but the net work done by all of them is zero) if the wire were just connected to a battery. I also understand that the net electrostatic force is zero (this is a closed path).</p>
<p>But here there is no battery, the current is induced by a change in the current of the wire</p>
<p>My intuition tells me that is the change in the current of the wire what changes the flux of the wire and the changing flux induces the emf in the loop. But not really sure of this...</p>
<p><strong>What's the nature of the induced current in the loop?</strong></p>
<p><strong>EDIT:</strong> The original exercise does not provide details on the set up, but my interpretation was the following: we start with two free-of-current wires: one is a loop, the other a straight line. We apply current on the straight wire, which induces an emf on the loop (which will stretch into a circle; this idea came from one of the sources I checked: <a rel="nofollow" href="https://physics.stackexchange.com/questions/239591/magnetic-potential-energy">https://physics.stackexchange.com/questions/239591/magnetic-potential-energy</a> ).</p>
<p>Souces:</p>
<p><a rel="nofollow" href="https://physics.stackexchange.com/questions/239591/magnetic-potential-energy">https://physics.stackexchange.com/questions/239591/magnetic-potential-energy</a></p>
<p><a rel="nofollow" href="https://physics.stackexchange.com/questions/266895/what-force-causes-the-induced-emf-of-a-loop-and-the-difference-between-a-loop?rq=1">https://physics.stackexchange.com/questions/266895/what-force-causes-the-induced-emf-of-a-loop-and-the-difference-between-a-loop?rq=1</a></p>
<p>Introduction to Electrodynamics by David Griffiths</p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3401/induce-large-current-flexible-explaining-does-stretch-circleFri, 08 Mar 2019 16:08:33 +0000question about 4-velocity
http://physics.qandaexchange.com/?qa=3396/question-about-4-velocity
<p>A particle is moving in the x, y plane at a speed of v = 0.80 and it is travelling an angle of 60 degrees<br>
above the x-axis.</p>
<p>(a) Rotate the spatial coordinates so that v lies along the x-axis and then construct the components of the 4-velocity for the particle.</p>
<p>(b) Construct the remaining orthonormal basis vectors for the particle in the rotated frame, then rotate the spatial coordinates back to find the basis vectors in the original frame.</p>
<p>(c) Perform the same steps above but this time begin by rotating the spatial coordinates so that <br>
v lies along the y-axis. Do you get the same result for the basis vectors after rotating back to the original frame? Should you? Draw a picture with ~v, the original (x, y) frame, and the two rotated frames to explain what is happening.</p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3396/question-about-4-velocityWed, 27 Feb 2019 22:32:29 +0000Electric field far away from a bunch of charges
http://physics.qandaexchange.com/?qa=3393/electric-field-far-away-from-a-bunch-of-charges
<p>I am given a bunch of charges and asked for the electric field at a field point far away (see image below).</p>
<p>What I would do is the following:</p>
<p><img src="https://i.imgur.com/UYHbwWv.jpg[/img]" alt=""></p>
<p>What I have done is applying Gauss' Law. However, in the lecture, another approach was used. </p>
<p>Firstly, the charges were treated per pairs , as dipoles. And as there are 4 +ive and 4 -ive, they cancel each other out and there is no first order contribution (i.e. $\frac{1}{r}$) .</p>
<p>Secondly, it was argued that this a quadrupole (using the same logic that above). Thus, the final answer would qualitatively be:</p>
<p>$$E \propto \frac{1}{r^3}$$ </p>
<p>Thus using two different methods one gets different answers; using method 1 one gets $E \propto \frac{1}{r^2}$ and using method 2 one gets $E \propto \frac{1}{r^3}$</p>
<p> Who is wrong and why? </p>
<p>Thanks.</p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3393/electric-field-far-away-from-a-bunch-of-chargesSun, 24 Feb 2019 20:14:51 +0000Find position and velocity at t=0?
http://physics.qandaexchange.com/?qa=3377/find-position-and-velocity-at-t-0
<p>Full question: </p>
<blockquote><p>An object moves with constant acceleration. At t= 2.50 s, the position of the object is x=2.00 m and its velocity is v= 4.50 m/s. At t= 7.00 s, v= -12.0 m/s. <br>
Find: <br>
(a) the position and the velocity at t= 0;<br>
(b) the average speed from 2.50s to 7.00 s, and <br>
(c) the average velocity from 2.50s to 7.00 s.</p>
</blockquote>
<p>I tried using the kinematic equations of motion for constant acceleration but my answers make no sense. </p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3377/find-position-and-velocity-at-t-0Tue, 05 Feb 2019 00:03:55 +0000What is the fraction of work per second by F is converted into heat.
http://physics.qandaexchange.com/?qa=3373/what-is-the-fraction-of-work-per-second-by-converted-into-heat
<blockquote><p>Two long parallel horizontal rails, a distance l apart and each <br>
has a resistance $\lambda$ per unit length are joined at one end by a <br>
resistance R. A perfectly conducting rod MN of mass m is free to<br>
slide along the rails without friction. There is a uniform magnetic <br>
field of induction B normal to the plane of paper and directed <br>
into the paper. A variable force F is applied to the rod MN such <br>
that, as the rod moves, a constant current i flows through R. <br>
What is the fraction of work per second by F is converted into heat.<br>
<img src="https://i.imgur.com/u4AZz4a.png" alt=""></p>
</blockquote>
<p><img src="https://i.imgur.com/Ps83YAo.jpg" alt=""></p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3373/what-is-the-fraction-of-work-per-second-by-converted-into-heatWed, 30 Jan 2019 13:44:47 +0000Find minimum distance between dipoles
http://physics.qandaexchange.com/?qa=3372/find-minimum-distance-between-dipoles
<p><img src="https://i.imgur.com/qrx8ozT.jpg" alt=""></p>
<p>My try :</p>
<p><img src="https://i.imgur.com/SUmBmaA.jpg" alt=""><br>
<img src="https://i.imgur.com/Y4IFqfs.jpg" alt=""><br>
But answer does not match.</p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3372/find-minimum-distance-between-dipolesWed, 30 Jan 2019 13:32:57 +0000Force that one half of uniformly charged solid sphere exerts on other half - Griffith 2.43
http://physics.qandaexchange.com/?qa=3368/force-uniformly-charged-solid-sphere-exerts-other-griffith
<p><img src="https://cdn.pbrd.co/images/HYuG13c.png" alt=""></p>
<p>I got the result mentioned, by considering the electric field as $\dfrac{\rho\cdot \vec{r}}{3\epsilon_o}$, and integrating carefully.</p>
<p>As problem asks to calculate the force on one part due to other, but the electric field I'm using here is the result of complete solid non conducting sphere, so why are we considering $E$ of the northern hemisphere to calculate force <strong>it</strong> experience. </p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3368/force-uniformly-charged-solid-sphere-exerts-other-griffithMon, 28 Jan 2019 06:18:15 +0000Electric field intensity at the centre of a solid hemisphere with uniform volume charge density
http://physics.qandaexchange.com/?qa=3360/electric-intensity-centre-hemisphere-uniform-volume-density
<p><img src="https://i.imgur.com/HtUlmlP.png" alt=""></p>
<p><a rel="nofollow" href="https://imgur.com/a/n0iohng">https://imgur.com/a/n0iohng</a></p>
<p>I am using Guru's Electromagneic Theory Fundamentals: <a rel="nofollow" href="https://www.amazon.ca/Electromagnetic-Field-Theory-Fundamentals-Singh/dp/0521116023">https://www.amazon.ca/Electromagnetic-Field-Theory-Fundamentals-Singh/dp/0521116023</a></p>
<p>For finding the electric field intensity, I am using the equation:<br>
<img src="https://i.imgur.com/G2nW912.png" alt=""><br>
<a rel="nofollow" href="https://imgur.com/a/RHS6SfY">https://imgur.com/a/RHS6SfY</a></p>
<p>I am unsure about what the value of r prime should be for a solid. </p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3360/electric-intensity-centre-hemisphere-uniform-volume-densitySun, 20 Jan 2019 03:09:55 +0000Rotating ball inside rotating cylinder.
http://physics.qandaexchange.com/?qa=3359/rotating-ball-inside-rotating-cylinder
<p>How do I proof: <img src="https://cdn.pbrd.co/images/HWY3y5g.png" alt=""> </p>
<p>Textbook solution :<br>
<img src="https://cdn.pbrd.co/images/HXsICHVJ.png" alt=""><br>
<img src="https://i.imgur.com/jTOB86r.png" alt=""></p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3359/rotating-ball-inside-rotating-cylinderFri, 18 Jan 2019 05:18:03 +0000Frequency modes of the rectangular shell
http://physics.qandaexchange.com/?qa=3357/frequency-modes-of-the-rectangular-shell
<p>This is task i received from my professor:</p>
<blockquote><p>The shapes of three natural modes having the frequencies $\omega_1, \omega_2, \omega_3$ of the rectangular shell are presented in the figure. The exciting pressure $p(t)$ applied uniformly all over the one side of the shell has the form $p(t) = Pe^{jωt}$. <br>
Make a sketch of the normal displacement of the gravity point of the shell against frequency, if the excitation frequency varies within bounds $0.5\omega_1< \omega <2\omega_1$ and static displacement of that point equals to $u_0$.</p>
</blockquote>
<p>Links to photo of frequency nodes (sorry for low quality)-><a rel="nofollow" href="https://ibb.co/b1nh3j9">1</a> .</p>
<p>Can somebody help me and tell me how i should get started?</p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3357/frequency-modes-of-the-rectangular-shellMon, 14 Jan 2019 21:42:44 +0000tension in wires from which a block is suspended
http://physics.qandaexchange.com/?qa=3349/tension-in-wires-from-which-a-block-is-suspended
<p><img src="https://cdn.pbrd.co/images/HVdTW5k.png" alt="1"></p>
<p>I am trying to figure out why the answer is T>W. Do you have any idea why? If so could you please explain. Thank you.</p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3349/tension-in-wires-from-which-a-block-is-suspendedSun, 06 Jan 2019 15:45:40 +0000How to solve this throwing ball off cliff question
http://physics.qandaexchange.com/?qa=3350/how-to-solve-this-throwing-ball-off-cliff-question
<p><img src="https://cdn.pbrd.co/images/HVdO2s0.png" alt=""></p>
<p>For b) I was curious why i couldn't use $s = ut + \frac12at^2$ as my equation as i had all the necessary known values. Instead to get the correct answer i had to use $v=u + at$.</p>
<p>Why is this so? Thank you for your time.</p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3350/how-to-solve-this-throwing-ball-off-cliff-questionSun, 06 Jan 2019 15:45:23 +0000Time period of small oscillation- disk and particle system
http://physics.qandaexchange.com/?qa=3346/time-period-of-small-oscillation-disk-and-particle-system
<p><img src="https://cdn.pbrd.co/images/HUWMQA2.jpg" alt=""></p>
<p>Attempt: </p>
<p>$y_{COM} = \dfrac{R}{3} = \dfrac {25}3$</p>
<p>$I = \dfrac 12 (2)R^2 + 1R^2 = 2\times 25 = 50 $</p>
<p>Now, T is given by: $T =2\pi \sqrt{\dfrac{I}{mgl}}$ where l is the distance of the centre of mass from the centre of rotation</p>
<p>So $T =2\pi \sqrt{\dfrac{50}{3 \times 10 \times \dfrac{25}{3}}} = 2\pi\sqrt{\dfrac{1}{5}}$</p>
<p>No option :( </p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3346/time-period-of-small-oscillation-disk-and-particle-systemFri, 04 Jan 2019 22:33:35 +0000Wave optics- number of minimas.
http://physics.qandaexchange.com/?qa=3345/wave-optics-number-of-minimas
<p><img src="https://cdn.pbrd.co/images/HUWujTQ.jpg" alt=""></p>
<p>Attempt: </p>
<p>Let m be the integer associated with $420 nm$<br>
and n be the integer associated with $540 nm$</p>
<p>$d \sin \theta = k \lambda $ $k\in Z$<br>
Clearly, </p>
<p>$m_{max} = 180$ </p>
<p>$n_{max} = 140 $</p>
<p>$(2m+1) \lambda_1 = (2n+1)\lambda_2$ (condition for dark fringes to overlap)</p>
<p>$\implies \dfrac{2m+1}{2n+1} = \dfrac 97$</p>
<p>$\implies m = \dfrac{1+7n +2n }{7}$</p>
<p>Hence, we obtain, for m to be an integer: $2n+1 = 7k$</p>
<p>$\implies n = \dfrac{7k-1}{2}$ where $k \in Z$</p>
<p>Now note that k must be odd since odd-1 = even </p>
<p>Thus, using $n \le 140$, $k_{max} = 39$</p>
<p>Now, we have to consider only odd values of k which are $1,3,...39$ = 20 numbers </p>
<p>Thus, we have 20 minimas on the upper side and 20 on the lower,<br>
Total minimas = $20+20 = 40$</p>
<p>But answer is $D$</p>
<p><strong>Question 1:</strong> What is wrong with my method? </p>
<p><strong>Question 2:</strong> Considering that this is a JEE Mains problem, what is the fastest 2 minute way to do it? </p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3345/wave-optics-number-of-minimasFri, 04 Jan 2019 22:01:11 +0000oblique collision of a rigid rod with a plane surface
http://physics.qandaexchange.com/?qa=3336/oblique-collision-of-a-rigid-rod-with-a-plane-surface
<blockquote><p>A uniform rod AB of length L is released from rest with AB inclined at angle 60° with horizontal, with the closer end of the rod to the ground, at a height 49m from it. Assuming the collision of the rod with the ground to be perfectly elastic, calculate the height the centre of mass of the rod will rebound after impact (assume ground to be frictionless).</p>
</blockquote>
Physics Problemshttp://physics.qandaexchange.com/?qa=3336/oblique-collision-of-a-rigid-rod-with-a-plane-surfaceTue, 01 Jan 2019 16:23:00 +0000Cylinder lying on conveyor belt
http://physics.qandaexchange.com/?qa=3323/cylinder-lying-on-conveyor-belt
<blockquote><p>You buy a bottle of water in the store and place it on the conveyor belt with the longitudinal axis perpendicular to the direction of movement of the belt. Initially, both the belt and the bottle are at rest. We can approach the bottle as one cylinder with radius $a$, mass $M$ and moment of inertia $I = M k^2$ ($k$ in units of length), in which the mass is not distributed uniformly. The speed of the belt at time $t$ is $V (t)$.<br>
a) Find an expression for the speed $v(t)$ of the centre of mass of the bottle.<br>
b) Explain why a bottle tends to start spinning on one moving band.</p>
</blockquote>
<p>What I have tried:</p>
<p>a) Having both longitudinal axis and belt's velocity vector perpendicular to each other <strong>on the same plane</strong> means that there will be rolling motion if we assume that static friction will be overcome. Let's disregard slippery effects as well.</p>
<p>Here I used an approach based on the fact that <strong>the bottle-belt-Earth system is nonisolated in terms of energy because the belt exerts an external force on the bottle, which means that it does work on the bottle.</strong> Therefore:</p>
<p>$$W = \Delta K_{tr} + \Delta K_{rot}$$</p>
<p>$$(F-f_f)d =v_{CM}^2 (\frac{I_{CM}}{a^2} + M)$$</p>
<p>$$v_{CM} = \sqrt{ \frac{2(F-f_f)d}{\frac{I_{CM}}{a^2} + M}} = \sqrt{ \frac{(F-f_f)d}{ M}}$$</p>
<p>The result I got does not seem to be incorrect; I checked dimensions and got $\frac{L}{T}$ .<strong>My question here is if I am right including the force F. I consider this force as a fictitious one, which is triggered by the non inertial frame in which the bottle is located: the conveyor belt.</strong> Note I am analysing the scenario from an inertial reference frame: The Earth (we regard it as inertial for known reasons). </p>
<p>b) If the static friction force was equal to the fictitious force F the cylinder <strong>would not spin</strong>. It would just move transitionally along the belt. Actually, if we were located on the belt, we would not see the cylinder move at all.</p>
<p><strong>In order to spin, the magnitude of F must exceed the magnitude of the maximum force of static friction. This friction force is recalled as force of kinetic friction.</strong></p>
<p><strong>EDIT</strong></p>
<p>From second (translation) Newton's law:</p>
<p>$$a_o= \frac{f}{M}$$</p>
<p>From second (rotation) Newton's law:</p>
<p>$$\tau = I \alpha = fa$$</p>
<p>$$k^2 \alpha= a_o a$$</p>
<p> $$\alpha = \frac{a_o a}{k^2}$$</p>
<p>Where $a_o$ is the acceleration of the cylinder measured from the ground.</p>
<p><strong>Assuming that the acceleration of the belt is constant</strong> ($a_b$):</p>
<p>$$ \frac{V}{t} = a_b$$</p>
<p>The acceleration of the cylinder with respect to the ground accounts for the acceleration of the belt and the angular acceleration of the cylinder (which has a negative sign because I considered the cylinder spinning clockwise i.e. the belt accelerating to the left and regarding that direction as the positive one). Therefore:</p>
<p>$$a_o = a_b - a\alpha$$</p>
<p>$$a_o = \frac{V}{t} -a\frac{a_o a}{k^2}$$</p>
<p>$$a_o = \frac{Vk^2}{(k^2 + a^2)t}$$</p>
<p>We know by kinematics that:</p>
<p>$$v_{cm} = \frac{Vk^2}{k^2 + a^2}$$</p>
<p>This makes sense to me. However I am confused because <strong>I was suggested that I should not assume that the belt moves with constant acceleration</strong> (please see kuruman's #2 comment <a rel="nofollow" href="https://www.physicsforums.com/threads/cylinder-lying-on-conveyor-belt.963471/">https://www.physicsforums.com/threads/cylinder-lying-on-conveyor-belt.963471/</a> ); Then how could I solve this problem?</p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3323/cylinder-lying-on-conveyor-beltSat, 22 Dec 2018 16:56:04 +0000floating cubical block
http://physics.qandaexchange.com/?qa=3319/floating-cubical-block
<blockquote><p>A cubical block of copper of side $10\ cm$ is floating containing mercury. Water is poured into the vessel so that the coper in the block just gets submerged. The height of the water column is?</p>
</blockquote>
<p>Solution goes like :</p>
<blockquote><p>Let height of water column be $h$, then $$\rho_w gh + \rho_{Hg} g(10-h)=\rho_{Cu} g 10$$</p>
</blockquote>
<p>I don't understand this, why are they writing pressure using Mercury?</p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3319/floating-cubical-blockThu, 20 Dec 2018 11:03:40 +0000Prove that the vector of acceleration always points towards the origin
http://physics.qandaexchange.com/?qa=3312/prove-that-vector-acceleration-always-points-towards-origin
<blockquote><p>A planet travels in an ellipse around the origin with the sun close to the origin. The planet's position in the ellipse is given by:</p>
<p>$x(t)=a\cos(kt)$</p>
<p>$y(t)=b\sin(kt)$</p>
<p>where $a>b$ and $k$ are constants and $0 ≤ t ≤ 2\pi$ ($t$ is a time variable).</p>
<p>The sun's position is given by $(x,y) = ( \sqrt{ a^2 − b^2}, 0)$.</p>
</blockquote>
<p>I've learnt that taking the derivative of the functions for position twice gives the functions for the acceleration. How would this look and how can I compare this answer with the functions for positions to show that the vector of acceleration is always pointed towards the origin?</p>
<p>In my attempt I've got that the acceleration is</p>
<p>$$a_x(t) = −ak^2cos(kt), a_y(t) = −bk^2sin(kt)$$</p>
<p>So the difference between position and acceleration is $−k^2$, provided that I'm correct so far. However I do not understand how this would show that the acceleration always is pointed towards the origin. Does the place of the sun even have any relevance? Considering that no masses and gravitation is taken account for.</p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3312/prove-that-vector-acceleration-always-points-towards-originSat, 15 Dec 2018 13:02:51 +0000Final charge on the capacitor and Charge on capacitor as a function time
http://physics.qandaexchange.com/?qa=3311/final-charge-the-capacitor-charge-capacitor-function-time
<p>In the given circuit diagram, initially charge on lower plate of capacitoris $Q_0$ = $CE/2$. Now switch is closed at t=0. Find<br>
1) Final charge on the capacitor<br>
2) Charge on capacitor asa a function time<br>
<img src="https://cdn.pbrd.co/images/HRxhcEy.jpg" alt=""></p>
<p>My try :<br>
<img src="https://cdn.pbrd.co/images/HRxhI0X.jpg" alt=""></p>
<p>In part b I tried to apply KVL but that would be quite lengthy.</p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3311/final-charge-the-capacitor-charge-capacitor-function-timeThu, 13 Dec 2018 12:16:20 +0000Check whether the followings are null, spacelike or timelike
http://physics.qandaexchange.com/?qa=3275/check-whether-the-followings-are-null-spacelike-or-timelike
<p>(a) <br>
$x^0=\int r^2+z^2d\tau$<br>
$x^1=\int r\sin\theta d\tau$<br>
$x^2=\int r\cos\theta d\tau$ <br>
$x^3=\int z d \tau$<br>
(b)<br>
$x^0= \sqrt3 ct$<br>
$x^1=ct$<br>
$x^2=ct_0 \sin(t/t_0)$<br>
$x^3=ct_0 \cos(t/t_0)$<br>
where $t_0$ is constant.</p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3275/check-whether-the-followings-are-null-spacelike-or-timelikeSun, 09 Dec 2018 11:01:29 +0000A projectile is ejected with vertical speed $v$ from the surface of a planet of mass $M$ and radius $R$
http://physics.qandaexchange.com/?qa=3295/projectile-ejected-with-vertical-speed-surface-planet-radius
<blockquote><p>A projectile is ejected with vertical speed $v$ from the surface of a planet of mass $M$ and radius $R$. Show that it comes to rest at a distance r from the centre of the planet where $$r=R/(1-Rv^2/2GM)$$ If $ v = c$ in the above example what will be the condition between M and R such that the planet acts like a Newtonian black hole.</p>
</blockquote>
<p>I have tried to solve it in the following way-</p>
<p>The height from the surface of the planet will be given by-<br>
$$y=vt-(1/2)gt^2$$<br>
when it comes to rest $v=0$ hence from the above equation we get<br>
$$r-R=(1/2)gt^2$$ <br>
From relation between g and G,<br>
$$g=Gm/r^2$$<br>
I have put all this values in $$y=vt-(1/2)gt^2$$<br>
but I am not getting the required answer. </p>
<p>Please tell me where did I made the mistake and correct me if going in the wrong direction. Thanking you. </p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3295/projectile-ejected-with-vertical-speed-surface-planet-radiusSun, 09 Dec 2018 11:01:24 +0000Rotation of L shaped rods after impulse
http://physics.qandaexchange.com/?qa=3304/rotation-of-l-shaped-rods-after-impulse
<blockquote><p>Two identical rod each of mass $m$ and length $\ell$ joined at one end and<br>
free to rotate about this end kept on smooth horizontal surface. An<br>
horizontal impulse $J$ is given to rod AB at centre and perpendicular to<br>
rod AB.<br>
<img src="https://cdn.pbrd.co/images/HQEyifd.png" alt=""><br>
<img src="https://cdn.pbrd.co/images/HQEyzJS.png" alt=""></p>
</blockquote>
<p><img src="https://cdn.pbrd.co/images/HQEyNxw.jpg" alt=""><br>
I am just able to deal the angular velocity about centre of but unable to proceed for individual rods.</p>
<p>Unable to proceed for second part.</p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3304/rotation-of-l-shaped-rods-after-impulseFri, 07 Dec 2018 17:01:43 +0000System of two ideal Fermi gases in three dimensions.
http://physics.qandaexchange.com/?qa=3294/system-of-two-ideal-fermi-gases-in-three-dimensions
<blockquote><p>1) What is the pressure of a gas of free bosons in the limit of vanishing temperature, $T \rightarrow 0$?<br>
2)Argue that for $T \rightarrow 0$ an ideal Fermi gas will have non-vanishing pressure $p_0 > 0$. <br>
We will now use this fact to study a system of two ideal Fermi gases in three dimensions.<br>
A free sliding piston separates two compartments labeled 1 and 2 with volumes $V_1$ and $V_2$ respectively. An ideal Fermi gas with $N_1$ particles with spin 1/2 is placed in compartment 1 and an ideal Fermi gas with $N_2$ particles with spin 3/2 is placed in compartment 2.</p>
</blockquote>
<p><img src="https://cdn.pbrd.co/images/HPrUESc.png" alt=""></p>
<p><img src="https://cdn.pbrd.co/images/HPrVk3f.png" alt=""></p>
<p><img src="https://cdn.pbrd.co/images/HPrVAq7.png" alt=""></p>
<p>As you notice, this problem has already been solved, but I do not understand the vast majority of it.</p>
<p>1) is OK.</p>
<p>2) I do not know how they got equation 15. It is stated to be a continuous approximation but not idea how to even start. </p>
<p>Actually, Griffiths has an interesting section in which treats the fermion distribution:</p>
<p><img src="https://cdn.pbrd.co/images/HPs57DJ.jpg" alt=""></p>
<p><img src="https://cdn.pbrd.co/images/HPs7CTH.jpg" alt=""></p>
<p>I know that the Fermi Dirac distribution (which is the one which interests us, since we are working with fermions) has a pretty well-known behavior as $T \rightarrow 0$ (please see figure 5.8 in Griffiths).</p>
<p>But I still do not know how to get it. </p>
<p>From here on I simply got lost. I mean, I have studied the free particle in QM but they go on with the density of states from EQ 16... I do not grasp it.</p>
<p>May you please shed some light on the provided solution (from EQ 15)?</p>
<p><strong>EDIT:</strong></p>
<p>Now I am stuck at EQ 19.</p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3294/system-of-two-ideal-fermi-gases-in-three-dimensionsThu, 29 Nov 2018 19:49:17 +0000The lean of a motorcyclist
http://physics.qandaexchange.com/?qa=3273/the-lean-of-a-motorcyclist
<blockquote><p>A motorcyclist takes a turn with a radius of $500 m$. Both the mass of the engine and the motorcyclist is $160 kg$ and their centre of mass lies $0, 5 m$ above the ground when it is perfectly vertical. His tangential speed is $60 m / s$ and its tangential acceleration is $4 m / s^2$.</p>
</blockquote>
<blockquote><p>a) Make a clear drawing in top view and back view with the<br>
speeds, accelerations and forces that affect the engine and motorcyclist.<br>
b) Calculate the speed and acceleration of the motorcyclist.<br>
c) Calculate the size of the components of all forces that act on<br>
the contact surface of the engine with the road.<br>
d) Calculate the angle at which the motorcyclist takes the turn (Hint: take its<br>
mass centre as the origin of the system).<br>
e) What is the apparent weight of the motorcyclist when he turns?* </p>
</blockquote>
<p>What I have done and what I do not know:</p>
<p>a)</p>
<p>I was not sure about what <strong>'top view and back view'</strong> meant so I did the following:</p>
<p>This is the diagram analysed from above: <a rel="nofollow" href="https://imgur.com/a/JtpNmfr">https://imgur.com/a/JtpNmfr</a></p>
<p>This is the diagram analysed from the ground: <a rel="nofollow" href="https://imgur.com/a/9AwOrWa">https://imgur.com/a/9AwOrWa</a></p>
<p>Note that the forces have just been drawn on the latest diagram because of clarity purposes. </p>
<p><strong>Is there anything missing on the diagrams?</strong></p>
<p>b) </p>
<p><a rel="nofollow" href="https://imgur.com/a/bbcrmPm">https://imgur.com/a/bbcrmPm</a></p>
<p><a rel="nofollow" href="https://imgur.com/a/0wPegtU">https://imgur.com/a/0wPegtU</a></p>
<p>NOTE: I assumed uniform circular motion. <strong>It makes sense for you what I did?</strong></p>
<p><strong>EDIT</strong></p>
<p>I was wrong assuming uniform circular motion because there is tangential acceleration; <strong>the motorcycle does not move with uniform speed.</strong></p>
<p>c) </p>
<p>Here we just have to use Newton's second law:</p>
<p>$$\sum F = Ma$$</p>
<p>As we are under uniform circular motion:</p>
<p>$$F = M a_c = M \frac{u^2}{OB}$$</p>
<p>However, we are not asked for calculating the centripetal force but the ones exerted on the road and the engine (always including the person's mass). These are:</p>
<p>The force exerted on the road by the engine:</p>
<p>$$F = Mg = -1569,6 N$$</p>
<p>The force exerted on the engine by the road:</p>
<p>This is simply the reaction force (Newton's third law):</p>
<p>N = 1569,6 N</p>
<p><strong>This seems too simple, am I missing something?</strong></p>
<p>d)</p>
<p>I do not know how to calculate the angle properly. Actually I got:</p>
<p>$$\alpha = \frac{ut}{OB}$$</p>
<p>But depends on time. <strong>Should I use kinematics to get the time and therefore the angle?</strong></p>
<p>e)</p>
<p><strong>Isn't the apparent weight just the normal force exerted on the motorcyclist? (i.e N = 1569,6 N)?</strong></p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3273/the-lean-of-a-motorcyclistSat, 24 Nov 2018 17:45:39 +0000Questions from a jumping kangaroo
http://physics.qandaexchange.com/?qa=3263/questions-from-a-jumping-kangaroo
<p><img src="http://i68.tinypic.com/2lc8wnn.jpg" alt=""></p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3263/questions-from-a-jumping-kangarooFri, 16 Nov 2018 15:38:20 +0000SHM with elastic collision.
http://physics.qandaexchange.com/?qa=3260/shm-with-elastic-collision
<blockquote><p>A ball suspended by a thread of length $l$ at the point $O$ on the wall, forming a small angle $\alpha$ with the vertical <a rel="nofollow" href="https://imgur.com/Ytg3szH">(Fig.)</a>. Then the thread with the ball deviated through a small angle $\beta$ $(\beta>\alpha)$ and set free. Assuming the collision of the ball with the wall to be perfectly elastic, find the oscillation period of such a pendulum.</p>
</blockquote>
<p><img src="https://i.imgur.com/g9zeh4t.png[/img]" alt=""></p>
<p>From <a rel="nofollow" href="https://imgur.com/a/7PTbF5W">fig</a> $2\theta$ part of SHM will be skipped over, $\cos\theta=\dfrac{\alpha}{\beta}\implies\cos2\theta=\dfrac{2\alpha^2-\beta^2}{\beta^2}$. So time it would be skpping over will be $t=\dfrac{1}{\omega}\cos^{-1}\bigg(\dfrac{2\alpha^2-\beta^2}{\beta^2}\bigg)$. On substrating from total time $T=2\pi\sqrt{\dfrac{l}{g}}$ gives me $T'=2\sqrt{\dfrac{l}{g}}\bigg[\dfrac{\pi}{2}+\sin^{-1}\bigg(\dfrac{2\alpha^2-\beta^2}{\beta^2}\bigg)\bigg]$. But in official answer argument of sin inverse is $\dfrac{\alpha}{\beta}$.</p>
<p>Please help.</p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3260/shm-with-elastic-collisionFri, 16 Nov 2018 13:31:41 +0000Diffusion with reflecting boundary
http://physics.qandaexchange.com/?qa=3254/diffusion-with-reflecting-boundary
<p><img src="https://cdn.pbrd.co/images/HNaMhdt.png" alt=""></p>
<p>What I have tried:</p>
<p><img src="https://cdn.pbrd.co/images/HNaMSPP.jpg" alt=""></p>
<p><img src="https://i.imgur.com/hls9bU5.png" alt=""></p>
<p>Note that my question is that how is it possible that I get $t = \infty$. It does not make sense for me (physically speaking). Where did I get wrong?</p>
<p>Please if there is information you require let me know. </p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3254/diffusion-with-reflecting-boundaryWed, 14 Nov 2018 20:07:35 +0000Angle made by the plane of hemisphere with inclined plane
http://physics.qandaexchange.com/?qa=3241/angle-made-by-the-plane-of-hemisphere-with-inclined-plane
<blockquote><p>A uniform thin hemispherical shell is kept static on an inclined plane of angle<br>
$\theta = 30$ as shown. If the surface of the inclined plane is sufficiently rough to prevent<br>
sliding then what is the angle $\alpha$ made by the plane of hemisphere with inclined plane .<br>
<img src="https://cdn.pbrd.co/images/HLyzG1g.jpg" alt=""></p>
</blockquote>
<p><img src="https://cdn.pbrd.co/images/HLyzXc6.jpg" alt=""></p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3241/angle-made-by-the-plane-of-hemisphere-with-inclined-planeSun, 04 Nov 2018 04:53:51 +0000Radial distribution of particle separation in a liquid at small distances
http://physics.qandaexchange.com/?qa=3233/radial-distribution-particle-separation-liquid-distances
<blockquote><p>Draw schematically the radial distribution function $g(r)$ for a Lennard-Jones fluid at low and high particle densities. Discuss in both cases the behavior at small $r$. At high densities $g(r)$ has some damped oscillations. Explain their origin and what would happen at long distances.</p>
</blockquote>
<p><strong>What I know:</strong></p>
<p>The radial distribution function $g(r)$ describes how density varies as a function of distance from a reference particle (<em>Wikipedia</em>).</p>
<p>Specifically in Lennard-Jones case, we have :</p>
<p><img src="https://i.imgur.com/Z41FKUL.png" alt="\[img\]https://i.imgur.com/Z41FKUL.png\[/img\]"></p>
<p>Here we can observe that if repulsion outweighs attraction, the curve will die out on the x axis. On the contrary, if it is the other way around, the curve will grow exponentially. For the sake of clarity, I would remark y = 0 as the Ideal Gas behaviour. </p>
<p>I have read that $g(r)$ vanishes at short distances, because the probability of finding two particles close to each other vanishes due to the repulsive part of the potential. At high densities $g(r)$ can show some damped oscillations: <br>
<img src="https://i.imgur.com/PqQPmcc.png" alt=""><br>
These oscillations express the preference of the particles to be found at specific distances from a reference particle at the origin. For instance in the LJ case, a first layer of particles will be localized closed to the minimum of LJ's potential, which is the origin of the first peak in $g(r)$.</p>
<p>This layer prevents other particles from getting close to it, which is what causes the first<br>
minimum in $g(r)$.</p>
<p><strong>What I do not know.</strong></p>
<p>1)The explanation: </p>
<p>'These oscillations express the preference of the particles to be found at specific distances from a reference particle at the origin'. </p>
<p><strong>How can particles have 'preference' to be at different distances?</strong> I think this is not a good physical explanation. I have been thinking about this and I would say that as there is a high density of particles at small distances, the repulsion force is exerted on these, which triggers such oscillations. Finally there is a point where they are so close to each other that the repulsion force provides them with an initial kinetic energy which will be equal to a final electrostatic potential energy of zero (selecting our zero of electrostatic potential energy at y=0) , and that is the moment when the curve dies out on the x axis. Do you agree with this explanation?**</p>
<p>2)Are we dealing with underdamped oscillations at high densities? Could you give an insight into these kind of oscillations (if what I have just said is not enough or incorrect)?</p>
<p>3)When we are dealing with long distances, would $g(r)$ tend to be one? What would we observe, the Ideal Gas behaviour? Why? Is it because there is no interaction between the particles?</p>
<p>As always, I am interested in explaining such phenomena from a physical point of view. </p>
<p><strong>ADDITIONAL INFORMATION RELATED TO THE RADIAL DISTRIBUTION:</strong></p>
<p>I came across the following slide:</p>
<p><img src="https://cdn.pbrd.co/images/HRnRJCC.png" alt=""></p>
<p>Which compares the structure factor $S(Q)$ with the radial distribution function $g(r)$. I know that the structure factor is a mathematical description of how a material <strong>scatters</strong> incident radiation, but <strong>how is the structure factor related to the distribution function (as this slide suggests)?</strong></p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3233/radial-distribution-particle-separation-liquid-distancesThu, 01 Nov 2018 16:00:05 +0000Liquid in a capacitor as dielectric (IE Irodov 3.144)
http://physics.qandaexchange.com/?qa=3225/liquid-in-a-capacitor-as-dielectric-ie-irodov-3-144
<blockquote><p>A parallel plate capacitor is located horizontally so that one of its plates is submerged into the liquid while the other is over its surface. The permittivity of the liquid is equal to $\epsilon$, its density is equal to $\rho$. To what height will the level of the liquid in the capacitor rise after its plates get a charge of surface charge density $\sigma$?</p>
</blockquote>
<p>This is a type of controversial problem, as it contains a different answer by the different author, two different answers provided for this are </p>
<p> $$1) \ h=\dfrac{(\epsilon-1)\sigma^2}{2\epsilon_o\epsilon\rho g}$$ $$2) \ h=\dfrac{(\epsilon^2-1)\sigma^2}{2\epsilon_o\epsilon^2\rho g}$$</p>
<p><a rel="nofollow" href="https://ibb.co/fYmek0">Solution for 1</a> and <a rel="nofollow" href="https://youtu.be/oyfo-TJEG28?t=31">solution for 2</a></p>
<p>Please help!</p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3225/liquid-in-a-capacitor-as-dielectric-ie-irodov-3-144Tue, 30 Oct 2018 01:37:42 +0000induced charge density at boundary surface
http://physics.qandaexchange.com/?qa=3216/induced-charge-density-at-boundary-surface
<blockquote><p>The space between the plates of a parallel plates capacitor is filled consecutively with two dielectrics layers $1$ and $2$ having the thickness $d_1$ and $d_2$ respectively and permittivities $\epsilon_1$ and $\epsilon_2$. The area of each plate is equal to $S$ find:<br>
1. The capacitance of the capacitor <br>
2. The density $\sigma'$ of the bound charges on the boundary plane if the voltage across the capacitor equals $V$ and the electric field is directed from layer $1$ to layer $2$.</p>
</blockquote>
<p>I managed to find $C_{eq}$ easily, for the second part I don't understand that word " <em>boundary plane</em>", I only know $\sigma'=\sigma\bigg(1-\dfrac{1}{\epsilon}\bigg)$ holds when there would have been just one plate, how to work on two such consecutive plates. Please help.</p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3216/induced-charge-density-at-boundary-surfaceSun, 28 Oct 2018 05:02:22 +0000Diffusion with an even number of reflecting boundaries
http://physics.qandaexchange.com/?qa=3211/diffusion-with-an-even-number-of-reflecting-boundaries
<p><img src="https://cdn.pbrd.co/images/HKoOk3T.png" alt=""></p>
<p>a)<br>
<img src="https://cdn.pbrd.co/images/HKoQ6sP.jpg" alt=""></p>
<p>This is the behaviour I expect from both concentrations at t= 0. Based on the theory of diffusion I would say that as t goes on, the Gaussian distributions will spread out and after a large number of collisions both concentrations will end up spreading out more or less evenly throughout the whole volume. Please let me know if this reasoning is wrong.</p>
<p>A doubt came to my mind as I imagine the same scenario if we had absorbing boundaries instead of reflecting ones. Therefore, does really matter the kind of boundary we are dealing with when we are trying to predict how the two concentrations (in this case) are going to spread out as time flows?</p>
<p>EDITED: </p>
<p>My initial idea about the identical scenario regarding either absorbing boundaries or reflecting ones was wrong. That is because after a long time in presence of absorbing boundaries, the concentration will end up being zero. </p>
<p>Related question: <a rel="nofollow" href="http://physics.qandaexchange.com/?qa=3113/solving-the-diffusion-equation-with-an-absorbing-boundary">http://physics.qandaexchange.com/?qa=3113/solving-the-diffusion-equation-with-an-absorbing-boundary</a></p>
<p>b)<br>
<img src="https://cdn.pbrd.co/images/HKoXG2o.jpg" alt=""><br>
Based on what I have said before, I would expect the limiting case to be that both concentrations were equal to each other.</p>
<p>EDITED: </p>
<p>Actually I was wrong as there is only one distribution of concentration, which tends to be uniform after a long time (as explained at a)).</p>
<p><strong>I have been looking for a deeper explanation and I came up with the idea that at the boundaries the current is zero:</strong></p>
<p>$$j =-D\frac{\partial c(+-a/2,t)}{\partial x} = 0$$</p>
<p><strong>Which means that c(x,t) has vanishing derivatives. How could this fact help to explain the limiting behaviour of the concentration after a long time?</strong></p>
<p>c)<br>
This household potential:<br>
<img src="https://cdn.pbrd.co/images/HKp12yu.jpg" alt=""></p>
<p>As we are dealing with the distribution of particles in thermal equilibrium, the first thing that came to mind when I read potential was the Boltzmann equation:</p>
<p>$$n = ke^{-V(x)/KT}$$</p>
<p>EDITED: </p>
<p><strong>I am coming up with the Boltzmann distribution because it can tell us the distribution of molecules. If the potential energy is known as a function of distance, then the proportion of them at different distances is given by this law. And we do know the potential, which is the square-well. So in the equilibrium concentration I should be able to check whether with the square-well potential we get:<br>
- When $|x| \le \frac{a}{2}$ we get a constant (the value of the concentration in equilibrium between the boundaries).<br>
- When $|x| > \frac{a}{2}$ we get zero (outside the barriers).<br>
But how can I check this?</strong></p>
<p>d) <br>
<strong>I came across an explanation. It is not detailed and I barely understand it. Please explain it if you see that it makes sense:</strong> (I do not know why pasteboard did not work. I had to use Imgur):</p>
<p><a rel="nofollow" href="https://imgur.com/a/8TLgeRe">https://imgur.com/a/8TLgeRe</a></p>
<p><a rel="nofollow" href="https://imgur.com/a/unkkyyQ">https://imgur.com/a/unkkyyQ</a> </p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3211/diffusion-with-an-even-number-of-reflecting-boundariesSat, 27 Oct 2018 15:15:35 +0000Charges induced on conducting plates.
http://physics.qandaexchange.com/?qa=3210/charges-induced-on-conducting-plates
<blockquote><p>Two infinite conducting plates $1$ and $2$ are separated by a distance $l$. A point charge $q$ is located between the plates at a distance $x$ from the plate $1$. Find the charges induced on each plate.</p>
</blockquote>
<p>Working on author's instruction, assuming $q$ to be spread uniformly on the plane through $q$ and parallel to plates, makes it easier to calculate electric field strength. Then to bring these distance into the picture we should work on potentials (as $E$ is known). But I don't know about potentials, should I take the potential difference between conductor to be zero, please explain everything in greater details.</p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3210/charges-induced-on-conducting-platesSat, 27 Oct 2018 05:01:02 +0000Relation between flux through lateral surface of a cylinder and flat parts.
http://physics.qandaexchange.com/?qa=3192/relation-between-flux-through-lateral-surface-cylinder-parts
<p>On solving IE Irodov 3.21, </p>
<blockquote><p>A ball of radius $R$ is uniformly charged with the volume density $\rho$. Find the flux of the electric field strength vector across the ball's section formed by the plane located at a distance $r_{0} < R$ from the center of the ball.</p>
</blockquote>
<p>From calculus obtained result is $$\boxed{\phi_1=\dfrac{\pi\rho r_o(R^2-r_o^2)}{3\epsilon_o}}$$</p>
<p>But if consider that flat surface as a flat surface of a cylinder then radius and height of such a cylinder will be $\sqrt{R^2-r_o^2}$ and $2r_o$ respectively, then from Gaus' Law flux through <strong>whole of cylinder</strong> is given by $$\boxed{\phi_2=\dfrac{\pi\rho (2r_o)(R^2-r_o^2)}{\epsilon_o}}$$</p>
<p>This is very similar to flux $\phi_1$ obtained for flat surface. More precisely $$\phi_1=\dfrac{\phi_2}{6}$$</p>
<p>So can we prove that flux through flat part of the cylinder is one-third of the total, and that through curved part is two-thirds of the total, in general?</p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3192/relation-between-flux-through-lateral-surface-cylinder-partsMon, 22 Oct 2018 12:21:17 +0000Oscillations of a rotating mass on a spring
http://physics.qandaexchange.com/?qa=3191/oscillations-of-a-rotating-mass-on-a-spring
<blockquote><p>A spring of constant $k$ is wrapped around a long rod. One end of the rod and spring are attached to a motor that rotates the rod with constant angular velocity $\Omega$. The other end of the spring is attached to a mass $m$. This mass slides along the rod as the spring expands and contracts. There is no friction or gravity in the problem. The equilibrium length of the spring is $r_{0}.$</p>
</blockquote>
<p><img src="http://i68.tinypic.com/2crm0pc.png" alt=""></p>
<blockquote><p>What is the oscillation frequency of the mass for small values of $\Omega$? What happens when $\Omega$ is large? Is the motion still simple harmonic motion?</p>
</blockquote>
<p>Since there is no gravity, the centrifugal force must equal the spring force so</p>
<p>$$m\Omega^{2}r=k(r-r_{0})$$</p>
<p>which leads to a constant $r$ since $\Omega$ is constant. So I am missing something basic here.</p>
<p>Maybe I should use energy conservation?</p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3191/oscillations-of-a-rotating-mass-on-a-springSun, 21 Oct 2018 20:39:57 +0000Deducing the mass of the Sirius system - Feynman exercises 3.17
http://physics.qandaexchange.com/?qa=3185/deducing-the-mass-of-the-sirius-system-feynman-exercises-17
<p><img src="https://cdn.pbrd.co/images/HJlk9yQ.jpg" alt=""></p>
<p>I do not even know how to try to deduce the mass M of the Sirius system in terms of that of the sun, as I do not not how to interpret the given data. </p>
<p>Could you give me a hint? </p>
<p><strong>EDITED AT THIS POINT</strong></p>
<p><strong>1) Estimating the distance to the Sirius binary system.</strong></p>
<p>I calculated the hypotenuse of the triangle $S E_1 SS$ (Sun - position of the Earth located at the top of a vertical circular orbit - Sirius System):</p>
<p>$$ \theta = 0.378^{\circ} arc \times \frac{1}{3600} \times \frac{2 \pi}{360} = 1.83 \times 10^{-6}arc sec $$</p>
<p>$$D = \frac{D'}{sin(\theta)} = 8.16\times 10^{16} m$$</p>
<p>Where:</p>
<p>D = the distance from the Earth to the Sirius binary system.</p>
<p>D' = Distance from the Sirius system to the Earth ($15 \times 10^{10} m$).</p>
<p>Here's an illustration of what I have done:</p>
<p><img src="https://cdn.pbrd.co/images/HJtrflM.png" alt=""></p>
<p><strong>2) Measuring the semi-major axis of the ellipse and estimating the period of the orbit from the figure.</strong></p>
<p>To compute the semi-major axis I have assumed the major axis is under the scale [0'',12'']. </p>
<p>As Sammy Gerbil said :'To measure the semi-major axis from the figure, magnify the diagram to fill your screen, place the edge of a sheet of paper along the diagonal line marked on the ellipse, mark off the ends of this line on the paper, then transfer the paper edge to the scale and read off the length in arc seconds. I get 13.8" for the major axis length, so the semi-major axis is a=6.9". The calculation is then:'</p>
<p>$$a=8.16\times 10^{16}m\times \frac{6.9}{3600}\times \frac{2\pi}{360} = 2.73 \times 10^{12}m$$</p>
<p>Now let's estimate the period of the orbit.</p>
<p>Is this the right thought? </p>
<p>$$\frac{dA}{dt} = SM \times SM \times \frac{d \theta}{2dt}$$</p>
<p>It will not be accurate as 'the two sides of most of the triangles are different'.</p>
<p>$A_1$:</p>
<p><img src="https://cdn.pbrd.co/images/HK5k6ab.jpg" alt=""></p>
<p>On process...</p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3185/deducing-the-mass-of-the-sirius-system-feynman-exercises-17Sat, 20 Oct 2018 15:50:53 +0000Find the angle between the $x$-axis and a vector
http://physics.qandaexchange.com/?qa=3105/find-the-angle-between-the-%24x%24-axis-and-a-vector
<blockquote><p>The $x$ component of vector $A$ is 25.0 m and the $y$ component is 40.0 m. <br>
(a) What is the magnitude of $A$? <br>
(b) What is the angle between the direction of $A$ and the positive direction of x?</p>
</blockquote>
<p>For (b) I tried using the formula $\tan \theta = \frac{a_y}{a_x} = \frac{40}{-25} = -1.6$, thus $\arctan(-1.6)=58$ degrees which does not match the answer key: $122$ degrees.</p>
<p>Any help is appreciated.</p>
Physics Problemshttp://physics.qandaexchange.com/?qa=3105/find-the-angle-between-the-%24x%24-axis-and-a-vectorSat, 20 Oct 2018 11:59:19 +0000